Random strings are harder to get, but still possible with a brute force approach (a cracker that tries every combination of n letters, digits and special characters that exist). This however takes very long and is not feasible for most.
"not feasible for most" is a gross understatement.
The MD5 hash is 128 bits long. This means that there are 340,282,366,920,938,463,463,374,607,431,768,211,456 values. This means that even if you could try a TRILLION combinations a second it would take you 10,790,283,070,806,014,188 years to break!
A brute force attack against MD5 won't work.
Sometime on Mar 31, Vinay Pai assembled some asciibets to say:
The MD5 hash is 128 bits long. This means that there are 340,282,366,920,938,463,463,374,607,431,768,211,456 values. This means that even if you could try a TRILLION combinations a second it would take you 10,790,283,070,806,014,188 years to break!
A brute force attack against MD5 won't work.
try a distributed attack. use the processing power of every computer on the planet.
actually, thinking of it this way, wouldn't it just make sense to create a reverse lookup table of every possible password and its encrypted value.
Yesterday @ 9:03pm Vinay Pai wrote:
The MD5 hash is 128 bits long. This means that there are 340,282,366,920,938,463,463,374,607,431,768,211,456 values. This means
Just curious. How did you calculate this?
according to xcalc 2^128 = 3.402823e+38
On Mon, 1 Apr 2002, Nikhil Joshi wrote:
The MD5 hash is 128 bits long. This means that there are 340,282,366,920,938,463,463,374,607,431,768,211,456 values. This means
Just curious. How did you calculate this?
according to xcalc 2^128 = 3.402823e+38
try python:
2L**128
or perl:
perl -e 'print sprintf("%39.0f", 2**128)'
Or you could use this to commify and print it:
my $n = reverse sprintf("%39.0f", 2**128); $n =~ s/\G(\d{3})(?=\d)/$1,/g; $n = reverse $n; print $n;
ask me why and ask me what.
----- Original Message ----- From: "Nikhil Joshi" Sent: Monday, April 01, 2002 8:13 AM
340,282,366,920,938,463,463,374,607,431,768,211,456
Just curious. How did you calculate this? according to xcalc 2^128 = 3.402823e+38
Arbitrary Precision Calculator - dc. Even "bc" would do, I guess.
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ambarish pathak -
Nikhil Joshi -
Philip S Tellis -
Vinay Pai