Sometime on Oct 31, Sameer D. Sahasrabuddhe assembled some asciibets to say: ^^^^^^^^^ letters of the alphabet ;) Some of them do carry out l33t replacement of letters with digits, so we get things like: 0 == [oO0] 1 == [liI] 3 == [eE] 4 == [A] 5 == [sS] 6 == [G] 7 == [tT] 9 == [g] With this kind of replacement, the given password might have been cracked, but not as fast as if we add certain diphthong replacements that I've been thinking of (in addition to the above): 1 == w | n | un | wun | won 2 == to{1,2} 3 == th | tr | r 4 == for | four | fore 5 == [fF] 6 == [xXsS] | sx 8 == ate? 9 == nn | n X == ck Z == S So, figure out this password: 491c81d3c163n70Xn6 (which is how long your password should be anyway). It's pronounceable, and seemingly hard to crack, but made up of dictionary words. My system should get close. Philip -- Why can't I ever build character at a Miami condo or a casino somewhere? -- Calvin Visit my webpage at http://www.ncst.ernet.in/~philip/ Read my writings at http://www.ncst.ernet.in/~philip/writings/ MSN philiptellis Yahoo! philiptellis AIM philiptellis ICQ 129711328