HI Friends I have a doubt in C++. when I pass an object to a function, the destructor gets called twice. This behaviour hasn't been mentioned in any books that I have read. Can someone please explain why this happens. In the below example the destructor for p1 gets called twice when it is passed as to the function f. _______________________C++ Code Start____________________________________ #include <iostream.h> #include <stdlib.h> class play { public: int i ; int j; play(int m){i=m; } ~play() {cout << "destructor called " << i <<" " << j << endl; } void f (play p) { p.j = 177; cout << " klkl " << endl; } }; int main(int argc, char *argv[]) { play p(1), p1(2); p.f(p1); cout << "Hello, World!" << endl; return EXIT_SUCCESS; } _______________________C++ Code End_____________________________________ ______________________Output Start__________________________________ klkl destructor called 2 177 destructor called 2 134514273 Hello, World! destructor called 2 134514273 destructor called 1 134519308 Press Enter to continue! _________________Output End_____________________________________ Regards Abhijeet D Mhatre Email: abhijeetmhatre(a)gmx.net -- http://mm.ilug-bom.org.in/mailman/listinfo/linuxers

I have a doubt in C++. when I pass an object to a function, the destructor gets called twice.