At 12:30 even 9/26/02 +0530, N Joshibaba wrote:
but the kernel architecture (monolithic / macrolithic / hybrid (?)) of Windows and Linux is different right ? Also there is difference between Windows 9x and NT kernel
AFAIK Linux kernel was written keeping in mind POSIX nd I guess POSIX nd Windows don't go together
AFAIK POSIX is an standard. M$ has full right to be compliant, *if* it so wants to.
Also I think you are assuming that Linux is the *best* kernel available (BTW what happened to HURD ?) which arguably is not the case
right, IMHO. GNU/Linux is the best choice due to its 'open' & 'free' nature. It is under constant and heavy development and one day (soon) may become the best. Stallman wants HURD to be in, but I think it lacks the developer following that Linux has.
I've seem ppl on Usenet (Microsoft Developers well versed with GNU/Linux) refer to Windows 2000 with reverence. I too think that Microsoft did come up with something 'stable' with Windows 2000.
Win2K is indeed stable. And, I suppose, a good secure OS to have if one does not mind paying the big bucks and wants professional technical support. The last truly useless piece of junk from M$ was windows95. Even windows98SE is quiet stable (though not as efficient as GNU/Linux and of course completely insecure).
I mean when I look at Windows Xp ; it iz a hybrid of Win 9x and Windows 2000 right?
Modified & improved Win ME interface on top of NT kernel. It is all eye-candy than genuine performance improvements, I suppose.
M$ already was inspired by the Mac OS X & the various good looking managers on X to name the last windows with an 'X' in it. :-)
quasi HSC pass, too! '-)
On Thu, Sep 26, 2002 at 03:44:23PM +0530, q u a s i wrote:
Win2K is indeed stable. And, I suppose, a good secure OS to have if one does not mind paying the big bucks and wants professional technical support.
Try this on windows (it's a java program. U can write it in C and compile with VC it will give same result)
class Crack { public static void main(String [] args) { for(;;) System.out.println("Hang up\t\b\b\b\b\b\b"); } }
It's just an infinite loop.
PLEASE: SAVE EVERYTHING BEFORE DOING THIS.
regards